| Author |
Message |
    
Jross
| | Posted on Friday, February 9, 2001 - 5:25 pm: |     |
Shown above are 4 men buried up to their necks in the ground. They can not
move so can only look forward. Between A and B is a brick wall which can
not be seen through. They know that between them are 4 hats, 2 x black and
2 x white, but they do not know which colour they are wearing. In order to
avoid being shot one of them must call out to the executioner the colour of
their hat. If they get it wrong, everyone will be shot. They are not
allowed to talk to each other and have 10 minutes to fathom it out.
Any answers? |
Dave
| | Posted on Friday, February 9, 2001 - 5:44 pm: | |
will the wall stop a bullet and which side is the executioner on? |
Jem
| | Posted on Friday, February 9, 2001 - 5:56 pm: | |
Jamie,
Does only one have to call out the color of his own hat? |
Eyespy
| | Posted on Friday, February 9, 2001 - 6:08 pm: | |
It's D.That was to easy. |
Dave
| | Posted on Friday, February 9, 2001 - 6:11 pm: | |
DON'T READ THIS IF YOU'RE STILL THINKING:
the answer is
.
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D would quickly call out his color if the two in front of him were both the same color, saving everyone from the executioner; as he remains silent, it becomes obvious to C that both his and B's hats are different. Seeing that B's is white, C can therefore presume his is black. |
Eb1154
| | Posted on Saturday, February 10, 2001 - 1:07 pm: | |
Here's another one.
Three men go to a hotel and share a room the room costs $30.00 so they pay $10.00 each and go to their room. Later the desk clerk realizes he has overcharged the three men (this has nothing to do with the reval, I swear) the room only cost $25.00 so he gives the bell boy $5.00 and tells him to return it to the three men. The bell boy decides it is to hard to split the $5.00 between the men so he pockets $2.00 and gives each man $1.00 back. The men now only paid $9.00 each for a total of $27.00 and the bell boy kept $2.00.
Where is the other $1.00? |
Lseltzer
| | Posted on Saturday, February 10, 2001 - 1:25 pm: | |
Because the room was assessed down by $5, the mil rate increased, adding another $1 to the room charge.
Actually, it's a nice tricky phrasing of the problem, but in fact the $1 doesn't exist. The men paid $9 times 3 for $27, overpaying by $2, which is what the bellboy kept. |
Eb1154
| | Posted on Saturday, February 10, 2001 - 1:56 pm: | |
Lseltzer,
Close but I think your wording is off by a little bit. |
Dave
| | Posted on Saturday, February 10, 2001 - 2:23 pm: | |
Math's wrong.
Question reads 27+2=29, so where's the dollar?
whereas it should be put:
Real Room rate $25
Bellboy's take $ 2 (of th $5 bill)
Rest of $5bill $ 3
--------------------
= $30 initially spent |
Eb1154
| | Posted on Saturday, February 10, 2001 - 2:31 pm: | |
Dave is correct. It's all how you phrase it. |
Dave
| | Posted on Saturday, February 10, 2001 - 2:32 pm: | |
| | | 5 | 3 | 7 | 8 | 9 | | 2 | 6 | 4 | 1 | x | | 8 | 0 | 2 | 0 | 4 | |
What is x? |
Eb1154
| | Posted on Saturday, February 10, 2001 - 2:50 pm: | |
Dave,
The answer is 5. |
Dave
| | Posted on Saturday, February 10, 2001 - 3:01 pm: | |
5 it is!
Here's another:
A census taker approaches a house and asks the woman who answers the door,"How many children do you have, and what are their ages?"
Woman: "I have three children, the product of their ages is 36, the sum of their ages is equal to the address of the house next door."
The census taker walks next door, comes back and says, "I need more information."
The woman replies, "I have to go, my oldest child is sleeping upstairs."
Census taker: "Thank you, I have everything I need."
Question: What are the ages of each of the three children? |
Janet
| | Posted on Saturday, February 10, 2001 - 5:25 pm: | |
My guess:
Either 12,3,1 (sum is 16) or 9,4,1 (sum is 14), which would put the houses next door to one another. But I have no idea what the kid sleeping upstairs has to do with it.
I take that back, I do. She has an oldest child. Another possibility is ages 6,6 and 1, but then there is no real "oldest" child. Those also add up to 13, putting the house on the other side of the street. The only other odd sum you could get is 21 with 18,2 and 1. |
Dave
| | Posted on Saturday, February 10, 2001 - 7:53 pm: | |
Not quite.
Hint: sums ain't the way to go here. |
Spw784
| | Posted on Saturday, February 10, 2001 - 8:15 pm: | |
If you live on some streets in Maplewood, the house numbers are consecutive. That is, House #21, is next door to #22.
Also, having worked for the 2000 census, the census taker (or ENUMERATOR) also needs the childrens' full names, races, ethnic backgrounds, and birthdates. (and thats for just the short form).
possibilities: 6, 3, 2 or 4, 3, 3,
I don't see what comparing the ages to the house next door has to do with it (other than the person went next door to see the number). Nothing indicates that the ages have anything to do with their OWN house number. |
Kap
| | Posted on Saturday, February 10, 2001 - 9:33 pm: | |
Three year old twins and a four year old. The next door address is 10. The house with three children is either # 12 or #8. |
Curb
| | Posted on Sunday, February 11, 2001 - 10:22 am: | |
7-8-4 |
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